2014 Final 1C

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Abigail Urbina 1K
Posts: 102
Joined: Thu Jul 27, 2017 2:01 am

2014 Final 1C

Postby Abigail Urbina 1K » Fri Mar 16, 2018 7:45 pm

You are trying to find the value for the enthalpy of vaporization, so you use q=mCdeltaT+(1/2)m*deltaHvap I understand how to do the algebra, however, I'm confused where the solutions got (5.4 * 10^-3 kJ/g C) for the value of C

Hazem Nasef 1I
Posts: 51
Joined: Tue Oct 10, 2017 6:13 am

Re: 2014 Final 1C

Postby Hazem Nasef 1I » Sat Mar 17, 2018 11:49 am

That is the specific heat capacity of the Potion in terms of kilojoules. This is taken from part 1B, where it is mentioned in the question as 5.4 J/C.g. This is then converted to kilojoules.


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