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### HW problem 4A.11

Posted: Sun Feb 03, 2019 12:32 am
A calorimeter was calibrated with an electric heater, which supplied 22.5 kJ of energy as heat to the calorimeter and increased the temperature of the calorimeter and its water bath from 22.45 degrees Celsius to 23.97 degrees Celsius. What is the heat capacity of the calorimeter?

I was trying to work this out but I'm not sure what equation to us??

### Re: HW problem 4A.11

Posted: Sun Feb 03, 2019 1:16 am
$C=\frac{22.5 kJ}{23.97^{O}C-22.45^{O}C}$