8.19

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Valeria Viera 1B
Posts: 60
Joined: Fri Apr 06, 2018 11:05 am

8.19

Postby Valeria Viera 1B » Mon Feb 04, 2019 9:30 pm

Hi I have no idea how to approach this problem:
Calculate the heat that must be supplied to a 500g Cu kettle containing 400g of water to raise its temperature from 22°C to 100°C

I know heat is q but I can’t seem to find an equation with q and temperature in the lecture notes.
Any help is appreciated!

Heesu_Kim_1F
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am

Re: 8.19

Postby Heesu_Kim_1F » Mon Feb 04, 2019 10:36 pm

You would use q=m x Cp x delta T, in which m = mass, Cp = specific heat capacity, and delta T= change in temperature, as your equation. Hope this helps!

Grace Kim 1J
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am
Been upvoted: 1 time

Re: 8.19

Postby Grace Kim 1J » Mon Feb 04, 2019 10:56 pm

For this problem, you would have to add the heat for copper and heat for water to find the total heat. We have to calculate the temperature rise for copper and water separately because they have different specific heats.

Your equation for part a should look like this:
Total heat= m x c x delta T (for copper) + m x c x delta T (for water)

Hope this helps!

Stevin1H
Posts: 89
Joined: Fri Sep 28, 2018 12:17 am

Re: 8.19

Postby Stevin1H » Wed Feb 06, 2019 12:09 am

For this problem, you would need to use the formula q=mCdeltat twice. This is because the specific heat capacity for copper and H2O are different. And after calculating both values of heat for copper and H2O, add the two values together to find total heat required.


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