7th edition 4C.7

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Searra Harding 4I
Posts: 68
Joined: Fri Sep 28, 2018 12:29 am

7th edition 4C.7

Postby Searra Harding 4I » Tue Feb 05, 2019 11:02 pm

It asks to find the enthalpy of vaporization and gives an amount of moles and an amount of heat. Why do we divide heat by moles to get the answer? Is this derived from another equation or did I miss something? Its simplicity confuses me lol

Patrick Cai 1L
Posts: 93
Joined: Fri Sep 28, 2018 12:25 am

Re: 7th edition 4C.7

Postby Patrick Cai 1L » Tue Feb 05, 2019 11:37 pm

The units of enthalpy are typically (energy)/(moles), usually either Joules/mole or kiloJoules/mole.

Stevin1H
Posts: 89
Joined: Fri Sep 28, 2018 12:17 am

Re: 7th edition 4C.7

Postby Stevin1H » Wed Feb 06, 2019 12:13 am

The enthalpy of vaporization refers to asking the amount of energy to vaporize 1 mole of the substance because the units of enthalpy is kJ/mol. So for this problem, you would do 4.76kJ/0.579mol to find that 8.22kJ of energy is required to vaporize 1 mole of CH4.


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