Homework 4C.9

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Jessica Li 4F
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Joined: Fri Aug 09, 2019 12:16 am

Homework 4C.9

Postby Jessica Li 4F » Fri Jan 31, 2020 10:56 pm

Does anyone know the answer for part a. of this question? Do you have to take into account the raised temperature of the water or the copper kettle, or both?

Thanks!

Katherine Wu 1H
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Re: Homework 4C.9

Postby Katherine Wu 1H » Fri Jan 31, 2020 11:40 pm

The heat change will be made up of two terms: one term to raise the temperature of the copper and the other to raise the temperature of the water:
q=(400.0g)(4.18J/celsius.g)(100.0celsius - 22.0celsius) + (500.0g)(0.38J/celsius.g)(100.0celsius-22.0celsius)

Jessica Li 4F
Posts: 115
Joined: Fri Aug 09, 2019 12:16 am

Re: Homework 4C.9

Postby Jessica Li 4F » Sat Feb 01, 2020 5:50 pm

Okay that's what I thought but wasn't sure. Thanks!


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