Textbook question 4D.3

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Paige Lee 1A
Posts: 136
Joined: Sat Sep 07, 2019 12:16 am

Textbook question 4D.3

Postby Paige Lee 1A » Sat Feb 01, 2020 12:22 pm

Could someone please explain how to get the correct answer for part b?
I keep getting 2.06kJ

The reaction of 1.40 g of carbon monoxide with excess water vapor to produce carbon dioxide and hydrogen gases in a bomb calorimeter causes the temperature of the calorimeter assembly to rise from 22.113 degC to 22.799 degC. The calorimeter assembly is known to have a total heat capacity (calorimeter con- stant) of 3.00 kJ?

(b) Calculate the internal energy change, deltaU, for the reaction of 1.00 mol CO(g).

Aman Sankineni 2L
Posts: 103
Joined: Fri Aug 30, 2019 12:17 am

Re: Textbook question 4D.3

Postby Aman Sankineni 2L » Sat Feb 01, 2020 1:28 pm

The heat of the reaction is equal to the negative heat of the calorimeter because the calorimeter is gaining heat from the reaction. Hence to calculate heat gained by the calorimeter, we use C(delta T). The question asks for the internal energy change for the reaction of 1.00 mol CO. We are given 1.40 g of CO or 0.04998 mol CO. To find out the heat for 1 mol of CO, we divide the value of C(delta T) by 0.04998 mol CO to get -41.2 kJ/mol CO.

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