Am I supposed to use this equation to find internal energy of a system that's at constant pressure?
Thanks
delta U = delta H - P delta V
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dtolentino1E
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Re: delta U = delta H - P delta V
yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
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Kristina Rizo 2K
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- Joined: Wed Sep 18, 2019 12:19 am
Re: delta U = delta H - P delta V
dtolentino1E wrote:yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
So when P is not constant we go back to delta U= q +w?
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Helen Struble 2F
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- Joined: Sat Aug 24, 2019 12:17 am
Re: delta U = delta H - P delta V
dtolentino1E wrote:yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
How would this change for a constant volume set up? Is delta U no longer equal to qp in that scenario?
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