Am I supposed to use this equation to find internal energy of a system that's at constant pressure?
Thanks
delta U = delta H - P delta V
Moderators: Chem_Mod, Chem_Admin
-
dtolentino1E
- Posts: 101
- Joined: Thu Jul 11, 2019 12:17 am
Re: delta U = delta H - P delta V
yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
-
Kristina Rizo 2K
- Posts: 105
- Joined: Wed Sep 18, 2019 12:19 am
Re: delta U = delta H - P delta V
dtolentino1E wrote:yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
So when P is not constant we go back to delta U= q +w?
-
Helen Struble 2F
- Posts: 97
- Joined: Sat Aug 24, 2019 12:17 am
Re: delta U = delta H - P delta V
dtolentino1E wrote:yes!
the change in internal energy (delta U) is usually calculated as heat (q) + work (w), but at constant pressure, q = delta H and w = -P(deltaV)
How would this change for a constant volume set up? Is delta U no longer equal to qp in that scenario?
Return to “Heat Capacities, Calorimeters & Calorimetry Calculations”
Who is online
Users browsing this forum: No registered users and 3 guests