3 posts • Page 1 of 1
A piece of copper of mass 20.0 g at 100.0 C is placed in a vessel of negligible heat capacity but containing 50.7 g of water at 22.0 C. Calculate the final temperature of the water. Assume that no energy is lost to the surroundings.
In the solutions manual, the equation to solve for the final temperature is given by heat lost by metal = –heat gained by water. This gives q = –q, and so mCT = –mCT. Once you substitute everything in, all of the variables are known except for Tfinal (final temperature) on both sides of the equation. So, the next step should be to isolate both sides with Tfinal so that you can find what its value is. But how do you know that the final temperature is the same when the metal loses heat and the water gains heat?
Who is online
Users browsing this forum: No registered users and 3 guests