4C.9A

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JamieVu_2C
Posts: 108
Joined: Thu Jul 25, 2019 12:16 am

4C.9A

Postby JamieVu_2C » Sun Feb 02, 2020 9:34 pm

(a) Calculate the heat that must be supplied to a copper kettle of mass 500.0 g containing 400.0 g of water to raise its temperature from 22.0 degrees C to the boiling point of water, 100.0 degrees C.

Why do you need to find the heat (q) for copper and the heat (q) for water and add them together? Why can't I just find the heat supplied to copper?

Long Luong 2H
Posts: 51
Joined: Thu Sep 19, 2019 12:16 am

Re: 4C.9A

Postby Long Luong 2H » Mon Feb 03, 2020 12:06 am

You are trying to heat the water to 100 degrees C and the copper is, in a sense, in the way. Both water and copper have different heat capacities so adding an amount of heat to one material isn't necessarily going to achieve the same temperature as adding the same amount of heat to another material. They both respond differently when heat is supplied to them.

ALegala_2I
Posts: 102
Joined: Thu Jul 11, 2019 12:17 am

Re: 4C.9A

Postby ALegala_2I » Mon Feb 03, 2020 10:24 am

The question is essentially asking how much energy it takes to heat the copper kettle which has its own unique specific heat capacity and how much energy it takes to heat the water. You have to perform two calculations to get the total change in energy.


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