Sapling 9 Week 3 and 4

[MichaelRaad_1F]

I was just confused on how to calculate the change in temperature for this problem because I know delta T is equal to final temperature - initial temperature but Im not sure how to find the final temperatures for this problem.

[shevanti_kumar_1E]

For this question you use heat gained (ice)= heat lost (hot water). The equation setup would be
mass(ice)*c(specific heat)*DeltaT(Tf-Ti)= -mass(hot water)*c*DeltaT. You would plug in the values given in the problem and solve for the value of Tf. Hope this helps!

[Anna Li 3B]

You can just look at it as the heat lost from the hot water will be heat gained by the cold water. The hot water will lose heat, since the cold water will bring its temperature down, so you can say q for the hot water is negative. We'll assume the heat transfer is perfect between the two samples of water, so q(cold water) = -q(hot water). Setting up the equations, you'll get

m(cold water)c(Tf-Ti)(cold water) = -m(hot water)c(Tf-Ti)(hot water)

The specific heat of water will be the same, but you'll need to convert the volume of water given into grams by using the density given. You have all the information needed in the problem to solve for the single variable Tf.