4D.5

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emmaferry2D
Posts: 139
Joined: Wed Sep 30, 2020 9:47 pm

4D.5

Postby emmaferry2D » Thu Mar 11, 2021 7:09 pm

For a certain reaction at constant pressure, ΔH
15kJ, and 22 kJ of expansion work is done on the system by compressing it into a smaller volume.What is ΔU for this process?

How would you do a problem like this?

I thought you would use the equation delta H= deltaU+PdeltaV but I am a little stuck on what to plug in to this equation

Eliana Witham 2H
Posts: 107
Joined: Wed Sep 30, 2020 9:48 pm
Been upvoted: 2 times

Re: 4D.5

Postby Eliana Witham 2H » Thu Mar 11, 2021 7:26 pm

We know that deltaU = q + w, and the question actually gives you the values for q and w. For a constant pressure, deltaH = q. Also, work is done on the system, meaning that your given work value is positive. You can add these numbers for the answer.

Alan Huang 1E
Posts: 101
Joined: Wed Sep 30, 2020 9:37 pm

Re: 4D.5

Postby Alan Huang 1E » Fri Mar 12, 2021 7:24 pm

Using ΔU = q + w:

We find that ΔU = ΔH + w

Just plug in values of ΔH = -15 and w = 22 we get

ΔU = -15 + 22
ΔU = +7 kJ


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