Textbook 4A. 9

[Kaitlin Joya 1I]

A piece of copper of mass 20.0 g at 100.0 C is placed in a calorimeter containing 50.2 g of water at 22.0 C. The final temperature of the mixture is 24. 8 C. What is the specific heat capacity of the metal? Assume that no energy is lost to the surroundigs.

How do you take into account both the copper and the water?

[Arjun_Anumula_3E]

Since the amount of energy that the copper gives off is equal to the amount of energy that the water takes in, you can set the equations up as so:

qw=-qc

(57)(4.18)(Tf-22) = -(20)(0.38)(Tf-100)

Solve for Tf, it should be between 22 and 100.

[Sara Shimabukuro 1A]

Since there is no heat lost in the reaction, the amount of energy lost by the copper and the amount of energy gained by the water must equal 0.

[MaiVyDang2I]

The heat lost by metal would be equal to the heat gained by water. So they'd be the same value with opposite sign. You can set the equation up with this and find T2, which is equal for both the metal and water.