Textbook Problem 4D.7

[Joanna Zhao 1J]

When we calculate PV = nRT, how do we know the temperature is 298K? It's not stated in the problem but it's in the solution manual. (Also, isn't the ideal gas temperature 273K?)

[Jayden Arevalo 2B]

I believe 298K or 25C is the standard temperature for the ideal gas law equation. This is because when converting 25C to Kelvin, we complete the process 25C + the conversion factor of 273.15, thus giving us the standard temperature of 298.15 K for the ideal gas law equation.

[Joanna Zhao 1J]

I believe 298K or 25C is the standard temperature for the ideal gas law equation. This is because when converting 25C to Kelvin, we complete the process 25C + the conversion factor of 273.15, thus giving us the standard temperature of 298.15 K for the ideal gas law equation.

They never specified 25C in the problem, and STP is traditionally 273K, isn't it? If they want us to use 25C, that's a huge assumption they're asking us to make! :D

[Andrewtrung Le 3A]

I think Lavelle has mentioned in lecture that standard temperature is 25 degrees C, which, if added with 273.15, yields ~298 K. Also, when dealing with the ideal gas law of PV = nRT, if I'm not mistaken, T should always be converted to K, because the only R values that are provided to us on the Constants and Equations sheet provided by the class all have units of K!

[Kailin Mimaki 2K]

1 degree celsius is equal to 273.15 kelvin, so we need to convert the standard temperature of 25 degrees celsius is to kelvins, so the calculation for temperature ends up 25 + 273.15=298.15 K. This is why we use 298.15K for pv=nrt. Hope this helped!