neutralization reaction from lecture (1/30)
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neutralization reaction from lecture (1/30)
In the lecture, the professor mentioned that the neutralization reaction of NaOH + HCl >> NaCl (aq) + H2O (l) had a pH of 7 and was an exothermic reaction. Is this always the case? Will all neutralization reactions be exothermic?
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Re: neutralization reaction from lecture (1/30)
Yes! If you get rid of the spectator ions:
NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O(l)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) --> Na+(aq) + Cl-(aq) + H2O(l)
OH-(aq) + H+(aq) --> H2O(l)
You can see that in the end, you just get the formation of water equation. Since you are forming a covalent bond, the reaction lowers in potential energy and is thus exothermic.
NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O(l)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) --> Na+(aq) + Cl-(aq) + H2O(l)
OH-(aq) + H+(aq) --> H2O(l)
You can see that in the end, you just get the formation of water equation. Since you are forming a covalent bond, the reaction lowers in potential energy and is thus exothermic.
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Re: neutralization reaction from lecture (1/30)
Yes, because NaOH is a strong base and HCl is a strong acid, they will both dissociate fully in water. This means that the solution will be neutralized and the pH of neutral water is 7.
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Re: neutralization reaction from lecture (1/30)
Hello! Yes, generally, all neutralization reactions are exothermic since bonds are being formed, meaning that energy is released by the reaction. Thus, in the reaction NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O(l) the formation of water exhibits more energy than is absorbed. As previously stated, getting rid of the spectator ions leaves the formation of water. I hope this was helpful!
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Re: neutralization reaction from lecture (1/30)
Hi! Yes, that will always be the case because Na and Cl are disregarded and we have H2O left and the pH of neutral water is 7!
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