## Fundamental E.1

WCano_4B
Posts: 6
Joined: Fri Sep 20, 2013 3:00 am

### Fundamental E.1

How do I cross cancel the given 1.0 mol Ag atoms? I know that I have Avogadro’s number over 1.0 mol Ag but do not know how to cancel the bottom portion to continue.

Khushboo_3D
Posts: 60
Joined: Wed Sep 18, 2019 12:19 am

### Re: Fundamental E.1

You have to multiply Avogadro's number with the diameter of the atoms which would be ( two times 144pm= 288pm) and also convert the diameter to meters by multiplying it by (10 to the power of negative 12). Once you multiply these three figures, you should get the answer.

Manav Govil 1B
Posts: 104
Joined: Sat Sep 07, 2019 12:19 am

### Re: Fundamental E.1

$1.00 mol Ag * \frac{6.0221* 10^{23} atoms}{1.00 mol Ag} * \frac{2*144pm}{1 atom of Ag}=1.73*10^{26}pm$

Nathan Rothschild_2D
Posts: 131
Joined: Fri Aug 02, 2019 12:15 am

### Re: Fundamental E.1

and then don't forget to convert your final units in meters not just pm, making it 1.73 x 10^14 m

005162520
Posts: 101
Joined: Tue Sep 24, 2019 12:17 am

### Re: Fundamental E.1

How would you convert pm to m?

Rory Simpson 2F
Posts: 106
Joined: Fri Aug 09, 2019 12:17 am

### Re: Fundamental E.1

pm is picometers, and 1 pm = 10^-12 m. So, 1.73*10^26 pm (10^-12 m/ 1 pm) = 1.73 * 10^14 m

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