Problem G.23

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Kelsey Ash 1D
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Joined: Wed Sep 18, 2019 12:16 am

Problem G.23

Postby Kelsey Ash 1D » Tue Oct 08, 2019 11:25 pm

For problem G.23 in the homework do you have to add the moles together of Cl in order to calculate the molarity of the element?

Abigail Menchaca_1H
Posts: 104
Joined: Sat Sep 07, 2019 12:19 am

Re: Problem G.23

Postby Abigail Menchaca_1H » Tue Oct 08, 2019 11:30 pm

You just find the moles of each compound and add them together and divide the sum by the volume in liters.

Katie Kyan 2K
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Re: Problem G.23

Postby Katie Kyan 2K » Tue Oct 08, 2019 11:47 pm

For G23 you find the number of moles of NaCl and KCl, add the moles together and divide by 0.100 L to get the Molarity. This is because there is a 1:1 ratio of moles of NaCl to moles of Cl- and a 1:1 ratio of moles of KCl to moles of Cl-. The molarity of Cl- should be 0.13 M.

Caitlyn Tran 2E
Posts: 100
Joined: Fri Aug 09, 2019 12:15 am

Re: Problem G.23

Postby Caitlyn Tran 2E » Wed Oct 09, 2019 12:01 am

Yes, you do have to add the number of moles of Cl- ions together in order to find the concentration of Cl- ions within the solution. More specifically, this can be accomplished by using dimensional analysis to convert the given masses of NaCl and KCl into the number of moles of Cl- ions. You then add these values to find the total number of moles of Cl- ions, which you can substitute into the M = n/V equation along with the given volume to get the final answer.


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