Sapling WEEK 4 #22

Moderators: Chem_Mod, Chem_Admin

Melanie Krahn 1C
Posts: 55
Joined: Wed Sep 30, 2020 9:34 pm

Sapling WEEK 4 #22

Postby Melanie Krahn 1C » Sun Nov 01, 2020 7:24 pm

Hello! I can't seem to get the right answer to this question. Could someone help explain how they solved?

You use an electron microscope in which the matter-wave associated with the electron beam has a wavelength of 0.0431 nm. What is the kinetic energy of an electron in the beam, expressed in electron volts?

Kaylee Messick 3J
Posts: 102
Joined: Wed Sep 30, 2020 9:54 pm

Re: Sapling WEEK 4 #22

Postby Kaylee Messick 3J » Sun Nov 01, 2020 7:30 pm

Hello! For this problem, you would use the wavelength provided to find the velocity using the de Broglie equation. Then you would use this velocity to find the kinetic energy in joules, and convert this answer to eV. Hope this helps!

Valerie Doan 3I
Posts: 115
Joined: Wed Sep 30, 2020 10:03 pm
Been upvoted: 1 time

Re: Sapling WEEK 4 #22

Postby Valerie Doan 3I » Sun Nov 01, 2020 7:36 pm

First, you use De Broglie's equation but re-arrange it to find velocity instead. So that would be . Using that velocity, you plug it into the kinetic energy equation . Your answer will be in Joules but you need to convert it to electron volts so divide E by .

Sarah Huang 3A
Posts: 70
Joined: Wed Sep 30, 2020 9:48 pm
Been upvoted: 1 time

Re: Sapling WEEK 4 #22

Postby Sarah Huang 3A » Sun Nov 01, 2020 7:49 pm

Melanie Krahn 1C wrote:Hello! I can't seem to get the right answer to this question. Could someone help explain how they solved?

You use an electron microscope in which the matter-wave associated with the electron beam has a wavelength of 0.0431 nm. What is the kinetic energy of an electron in the beam, expressed in electron volts?


Hi Melanie! In order to find the kinetic energy in electrovolts,you first need to convert the wavelength into the energy using E = hv. But since you have a wavelength, you convert the equation to E = (hc)/lambda, the lambda being the wavelength gave you. They gave you 0.0431 nm, so you convert that to meters. Since it is in nanometers, you know that nano indicates 10^-9, so you wavelength is 0.0431 x 10^-9m.

Using that, your current equation is now E = ((6.626*10^/34J*s)(2.998*10^8 m/s))/ (0.0431 x 10^-9m). Solve that equation, make sure to check out your units, and then once you get your answer, which is in Joules, you convert it to electrovolts (eV).

In order to do that, you use the conversion factor 1 eV = 1.602 * 10^-19 J.

I hope that helps!

My way isn't necessarily the right way though since I use the equations for a photon, but you can definitely use the de broglie wavelenth to figure it out too! Just remember to use your conversions and check your units.

reva_bajjuri
Posts: 117
Joined: Fri Oct 02, 2020 12:17 am

Re: Sapling WEEK 4 #22

Postby reva_bajjuri » Sun Nov 01, 2020 9:54 pm

for this problem, would you use the 4 sig figs in the conversion from joules to electo volts or are those not significant figures?

Britney Tran IJ
Posts: 103
Joined: Fri Aug 30, 2019 12:18 am

Re: Sapling WEEK 4 #22

Postby Britney Tran IJ » Sun Nov 01, 2020 10:03 pm

reva_bajjuri wrote:for this problem, would you use the 4 sig figs in the conversion from joules to electo volts or are those not significant figures?

I believe you would use the sig figs from the value given in the problem (0.0431). Therefore, your answer should have 3 sig figs.


Return to “SI Units, Unit Conversions”

Who is online

Users browsing this forum: No registered users and 8 guests