Quiz prep 3 question 1  [ENDORSED]

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Eman_Burney_1D
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Joined: Wed Sep 21, 2016 2:57 pm

Quiz prep 3 question 1

Postby Eman_Burney_1D » Sun Mar 05, 2017 11:30 pm

Question 1 of quiz 3 preparation asks to name the compound shown below (ignore the periods, I had to use them to keep the formatting):
......................................CH(CH3)2
......................................|
CH3CH2CH2CH2CH2CH2CHCH2CH2CH3

For the answer, I got 4-isopropyldecane, however I did not get 4-(1-methylethyl) decane. How is the second version found? I believe someone had asked this under the quiz 3 prep topic in the announcement section, but I am still a bit unclear on the solution. Thank you!

Brandon_Williams_3E
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Re: Quiz prep 3 question 1

Postby Brandon_Williams_3E » Sun Mar 05, 2017 11:56 pm

The first answer is using the common name. The second answer is using the systematic IUPAC naming. Both are correct and can be used interchangeably.

Eman_Burney_1D
Posts: 15
Joined: Wed Sep 21, 2016 2:57 pm

Re: Quiz prep 3 question 1

Postby Eman_Burney_1D » Mon Mar 06, 2017 12:02 am

But if I was asked to use the IUPAC name, how would you go about doing that? How do you get 4-(1-methylethyl) decane?

Emily Wang 1H
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Re: Quiz prep 3 question 1  [ENDORSED]

Postby Emily Wang 1H » Mon Mar 06, 2017 12:34 am

For the IUPAC name, you get decane from the chain with 10 carbons. The 4 comes from the isopropyl group being attached to the 4th carbon from the left. You wouldn't start from the right because then it would be 6, and you always want the lowest number for IUPAC naming. Then, the 1 comes from the isopropyl group, where the ethyl is attached to the methyl. Putting it all together, you get 4-(1-methylethyl) decane.


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