Final 2013

Moderators: Chem_Mod, Chem_Admin

Blake_Katsev_2E
Posts: 113
Joined: Wed Sep 21, 2016 1:57 pm

Final 2013

Postby Blake_Katsev_2E » Mon Mar 13, 2017 4:37 pm

Do we need to know how to do question 6B/how do we do it?

Chem_Mod
Posts: 16491
Joined: Thu Aug 04, 2011 12:53 pm
Has upvoted: 349 times

Re: Final 2013

Postby Chem_Mod » Mon Mar 13, 2017 10:29 pm

Please be more specific in your question. What is question 6B regarding?

Blake_Katsev_2E
Posts: 113
Joined: Wed Sep 21, 2016 1:57 pm

Re: Final 2013

Postby Blake_Katsev_2E » Tue Mar 14, 2017 9:25 am

as in hexadecanol, i dont recall learning how to draw these particular structures.

Jimmy Zhou 3D
Posts: 30
Joined: Sat Jul 09, 2016 2:00 am

Re: Final 2013

Postby Jimmy Zhou 3D » Wed Mar 15, 2017 12:03 pm

Perhaps it is better to understand the general concept then certain structures. For example hexadecanol is a open chain of 16 carbons with an alcohol fucntional group on carbon 1. We know the naming up to 10 carbons, but we can imply that hexadcanol is 16 carbons using the prefixes. I feel like this is a possible test question.

Sean_Yue_1E
Posts: 9
Joined: Wed Nov 18, 2015 3:00 am
Been upvoted: 1 time

Re: Final 2013

Postby Sean_Yue_1E » Mon Mar 20, 2017 7:38 am

For naming chains with over 10 carbons, I think you just have to put the 10th value ahead of 1's value for example hexa deca would be 16 penta deca would be 15 etc. If there is no numbering for the ol/ OH group then you can assume it's on number 1. Hexadecanol can also be written as hexadecan-1-ol.


Return to “*Alkanes”

Who is online

Users browsing this forum: No registered users and 1 guest