Winter Final 2012 Question 6B

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Michelle Yu 1L
Posts: 34
Joined: Fri Sep 25, 2015 3:00 am

Winter Final 2012 Question 6B

Postby Michelle Yu 1L » Sat Mar 12, 2016 9:14 pm

for the 1-isopropyl -3- neopentylcyclohexane, how do you know it is neopentyl?

jbcarton
Posts: 11
Joined: Fri Sep 25, 2015 3:00 am

Re: Winter Final 2012 Question 6B

Postby jbcarton » Sat Mar 12, 2016 10:12 pm

You know it is neopentyl because it has 3 carbons branching off of from one carbon (giving it the neo) and there are a total of 5 carbons in the substituent (making it pentyl). In other problems it looks like a cross but it an also be drawn like this.

Michelle Yu 1L
Posts: 34
Joined: Fri Sep 25, 2015 3:00 am

Re: Winter Final 2012 Question 6B

Postby Michelle Yu 1L » Sat Mar 12, 2016 11:04 pm

There was a similar problem where it was drawn like the this neopentyl but instead of neo it was named tert in final 2012 the first one of 6D. so I am confused between the two.

VinayK 2B
Posts: 10
Joined: Fri Sep 25, 2015 3:00 am

Re: Winter Final 2012 Question 6B

Postby VinayK 2B » Sun Mar 13, 2016 11:08 pm

A neo group is a group that has three methyl groups at the end and AT LEAST five carbons total, ie there is a secondary carbon connecting the branching side chain to the main chain. A tert-butyl group is a branching side chain that contains three methyls at the end and connects to the main chain via the tertiary carbon (once it is bonded to the chain, it is quaternary). The tert-butyl group is a sub-class of the neo branching.


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