2013 FINAL Q6A

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Hung_Sabrina_3N
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Joined: Fri Jul 22, 2016 3:00 am

2013 FINAL Q6A

Postby Hung_Sabrina_3N » Fri Mar 17, 2017 5:38 pm

Why is the compound 1,5,5,6-tetramethylcyclohex-1-ene not named 2,3,4,4-tetramethylcyclohex-1-ene? Wouldn't the overall numbering of the second one be lower than the first except for the the first substituent?

Susanne_Taavitsa_2J
Posts: 20
Joined: Sat Jul 09, 2016 3:00 am

Re: 2013 FINAL Q6A

Postby Susanne_Taavitsa_2J » Fri Mar 17, 2017 6:15 pm

Since one of the methyl substituents is on the carbon carbon double bond, it gets numbered as 1. And since the double bonds in cycloalkenes are given the number 1 and 2 when numbering the carbons in the ring, the numbers are given in a counterclockwise order.

giareyes_2B
Posts: 20
Joined: Wed Sep 21, 2016 2:58 pm

Re: 2013 FINAL Q6A

Postby giareyes_2B » Fri Mar 17, 2017 10:51 pm

For this same problem, why is the 1 Carbon identified as being sp2? I thought sp2 meant 3 areas of electron density, but by this reasoning shouldn't carbons 2 and 3 be circled since they both have 3 bonds?

sboutros2B
Posts: 24
Joined: Sat Jul 09, 2016 3:00 am

Re: 2013 FINAL Q6A

Postby sboutros2B » Sat Mar 18, 2017 7:02 pm

I have the same exact question. If someone could explain to me why carbon 2 and 3 isn't circled it would be greatly appreciated (:

regina_ho_3A
Posts: 13
Joined: Fri Jul 15, 2016 3:00 am

Re: 2013 FINAL Q6A

Postby regina_ho_3A » Sat Mar 18, 2017 7:17 pm

Carbon 2 is circled, if you check the solutions in the book. Carbon 3 is not sp2 hybridized, since it is bonded to 2 other carbon atoms and 2 hydrogen atoms.


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