COURSE READER PG 105

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704578485
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COURSE READER PG 105

Postby 704578485 » Mon Feb 29, 2016 9:23 pm

On the course reader on page 105 the second molecule on the page has the name 3,6 dimethyl-3octene. In lecture we went over how more specifically there should be and (E) or trans at the front of the name. Why is this though? I see that on the 3rd carbon the atom that it is bonded to with highest atomic number is a carbon but for the 2nd carbon in the chain why do you CH2 carbon over the CH3 carbon?

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Re: COURSE READER PG 105

Postby Chem_Mod » Tue Mar 01, 2016 11:48 am

Because the methyl is attached to 3 hydrogens (CH3), and the ethyl carbon is attached to 2 hydrogens and another carbon (CH2-C), it is preferred. Because each substituent is just a saturated alkane, you can also just choose the largest substituents which are ethyl and propyl, which give the (E) or (trans) conformation.


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