Sig Figs when finding Mol

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Grace Kim 1J
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Sig Figs when finding Mol

Postby Grace Kim 1J » Wed Oct 03, 2018 1:01 pm

Hi Everyone!
I was wondering if sig figs matter when finding the mol.

For Example (Module 1: #5)
Mol of C: 54. 82 g/12.01 g. mol^-1= 4.56 mol OR 4.564 mol?

Regardless of which one we use, I know that we would get the same answer in the end after dividing by the smallest number, but I was wondering if we would get docked points for not using sig figs when showing our work for calculating mols. Thanks!

monikac4k
Posts: 56
Joined: Fri Sep 28, 2018 12:25 am

Re: Sig Figs when finding Mol

Postby monikac4k » Wed Oct 03, 2018 1:14 pm

If the number of moles is the answer to the problem, you would want to round according to the number of sigfigs, which in this case seems to be 4 significant figures. However, if you are going to continue using the number in further calculations, you should continue using the longer version. According to my understanding, significant figures are most important in the final answer, not during the calculations.

705152867
Posts: 28
Joined: Fri Sep 28, 2018 12:18 am

Re: Sig Figs when finding Mol

Postby 705152867 » Wed Oct 03, 2018 2:44 pm

As long as your work is shown to lead to the answer with the correct number of sig figs, I don't think getting points docked would be an issue :)

KarlaArevalo2F
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Re: Sig Figs when finding Mol

Postby KarlaArevalo2F » Wed Oct 03, 2018 10:33 pm

It's always best to use the most amount of sig figs when continuing a problem, but always refer to the sig fig rules (which is mostly using the least number of sig figs I believe) when writing the final answer.

Srikar_Ramshetty 1K
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

Re: Sig Figs when finding Mol

Postby Srikar_Ramshetty 1K » Wed Oct 03, 2018 10:41 pm

A good rule to remember when dealing with significant figures, especially in division and multiplication problems, is that your answer cannot be more significant than the least significant value present in the equation. For example, if you divide 4.56 by 2.1 (i.e. 4.56/2.1), then your answer would be 2.2, rather than 2.17. This is because 2.1 contains only 2 significant figures and getting an answer that is more precise than one of the values in the calculation would detract from the answer's validity. The values you provided as an example both contain 4 significant figures, therefore, your answer should also contain the same amount of significant figures.

Hope this helped!
- Srikar Ramshetty


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