F.7
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- Posts: 23858
- Joined: Thu Aug 04, 2011 1:53 pm
- Has upvoted: 1253 times
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- Posts: 23858
- Joined: Thu Aug 04, 2011 1:53 pm
- Has upvoted: 1253 times
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- Posts: 60
- Joined: Fri Sep 28, 2018 12:18 am
Re: F.7
(a) If we assume the compound to be 100g, then 88.8 g is M and 11.2 g would be O. First, find the molar mass of the whole compound through stoichiometry: (100 g M2O/11.2 g O) x (16.00 g O/1 mol O) x (1 mol O/1 mol M2O) will result in 143 g/mol M2O. Since O's molar mass is 16.00 g/mol, the molar mass of M2 is 143-16=127 g/mol, meaning the molar mass of the metal M is 127/2= 63.5 g/mol.
(b)Look on the periodic table, and the closest metal with the molar mass of 63.5 g/mol is Copper. Thus, its name would be Cu2O, or copper(I) oxide. Hope this helps!
(b)Look on the periodic table, and the closest metal with the molar mass of 63.5 g/mol is Copper. Thus, its name would be Cu2O, or copper(I) oxide. Hope this helps!
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