1 A 15 7th Edition  [ENDORSED]

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1 A 15 7th Edition

Postby Andre_Galenchik_2L » Mon Oct 22, 2018 5:56 pm

In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line.

I understand how to solve this question it is just that I am confused why the answer is n=1 to n=3 and not n=3 to n=1. Doesn't emission mean an electron going down an energy level?

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Re: 1 A 15 7th Edition  [ENDORSED]

Postby Chem_Mod » Mon Oct 22, 2018 7:05 pm

Typo. Answer is n = 3 to n = 1 as energy is emitted.

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