Atomic Spectra

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Madison Gil 3D
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Joined: Fri Sep 28, 2018 12:23 am

Atomic Spectra

Postby Madison Gil 3D » Mon Oct 22, 2018 7:58 pm

The meter was defined in 1963 as 1,650,763.73 wavelengths of radiation emitted by krypton-86 (it has since been redefined). What is the wavelength of this krypton-86 radiation? To what region of the electromagnetic spectrum does this wavelength correspond (i.e. infrared, ultraviolet, x-ray, etc.)? What energy does one photon of this radiation have?
How would you start this problem and what equation(s) would you use? Thank you.

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Joined: Fri Sep 28, 2018 12:17 am

Re: Atomic Spectra

Postby ChathuriGunasekera1D » Mon Oct 22, 2018 8:10 pm

Okay I think you would start off by dividing 1 meter by 1,650,763.73 wavelengths to get the length of one wavelength of Krypton-86. This makes sense because the units become meters/one wavelength and that's what wavelength measures.

1/1,650,763.73 = 6.058 x 10-7 m which is 605.8 nm. That is in the visible light area. From there you can use c = wavelength * v and E = hv to get energy per photon.

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