## Units of De Broglie's Equation

$\lambda=\frac{h}{p}$

Jack Mitchell 3J
Posts: 24
Joined: Fri Sep 28, 2018 12:24 am

### Units of De Broglie's Equation

I understand that the SI unit for wavelength is meters, but when doing the calculation, how do you cancel the other units to get meters.

pamcoronel1H
Posts: 45
Joined: Fri Sep 28, 2018 12:25 am

### Re: Units of De Broglie's Equation

Since it is h/mv, and J=kg×m^2 the units are:
(kg×m^2)×s/kg×(m×s)
The kg, s, and one m cancel out, leaving only one m on top, which is your unit for wavelength :)
Last edited by pamcoronel1H on Thu Oct 25, 2018 10:33 pm, edited 1 time in total.

Henry Krasner 1C
Posts: 64
Joined: Fri Sep 28, 2018 12:15 am

### Re: Units of De Broglie's Equation

Lambda=h/mv
Lambda is in meters
h- Planck's constant (6.63x10^(-34))J s or (kg m^2.s^2) s
m-mass in kg
v- velocity in m.s
Everything cancels out so that Lambda, or wavelength, is just in meters.

Yiting_Gong_4L
Posts: 69
Joined: Fri Sep 28, 2018 12:25 am

### Re: Units of De Broglie's Equation

Wavelength can also be converted from meters to nanometers and written in that unit.

Jack Mitchell 3J
Posts: 24
Joined: Fri Sep 28, 2018 12:24 am

Thanks Guys