7th edition 2B.7

Moderators: Chem_Mod, Chem_Admin

Alyssa Bryan 3F
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am
Been upvoted: 1 time

7th edition 2B.7

Postby Alyssa Bryan 3F » Sun Nov 04, 2018 3:57 pm

In the given lewis structure, how are you able to identify the unknown element?

Posts: 19168
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 833 times

Re: 7th edition 2B.7

Postby Chem_Mod » Sun Nov 04, 2018 8:06 pm

It might be better if you post the actual question.

Posts: 39
Joined: Fri Sep 28, 2018 12:25 am

Re: 7th edition 2B.7

Postby rachana_korapati3C » Sun Nov 04, 2018 8:59 pm

From counting up all the lone pairs and bonds, you can calculate the total number of valence electrons for the compound. In this case, there are 32 VE. The diagram shows you how many Cl and O atoms are in the compound, so using that you can calculate the number of VE that come from those two atoms. 32 VE= 3(7) + 6 + E --> 5VE. It says that the unknown element is in period #, therefore you can deduce that the element is P because it's the only element in period 3 with 5 VE.

Return to “Lewis Structures”

Who is online

Users browsing this forum: No registered users and 2 guests