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If you have an sp2 hybridized orbital, there is one p orbital left that is not hybridized. When you are filling electrons into the orbitals, the energy difference between sp2 and p is very small (because you can think of sp2 as an average of s and 2 p orbitals), so it is more energy favorable for the electrons to enter into the p orbital rather than having a lone pair in one of the hybridized orbital. When a bond forms with the unhybridized orbital, it is a pi bond.
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