churro 38

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churro 38

Postby 405169322 » Sat Dec 08, 2018 12:50 am

between H2S and H2Se why does H2Se have a higher boiling point even though it has a weaker dipole-dipole?

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Re: churro 38

Postby Mahir_Hasan2C » Sat Dec 08, 2018 1:05 am

Due to the fact it has a higher molar mass it is a bigger molecule, thus it requires more energy.

Richard Ku 4H
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Re: churro 38

Postby Richard Ku 4H » Sat Dec 08, 2018 2:39 am

The mass of the molecule with Se is much greater, and hence will experience a greater level of London dispersion forces. Mass and London dispersion forces are proportional.

Claudia Luong 4K
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Re: churro 38

Postby Claudia Luong 4K » Sat Dec 08, 2018 7:51 am

Although H2S has stronger dipole-dipole forces, the LDFs in H2Se are stronger than that of H2S. These forces are strong enough to overcome even the dipole-dipole forces of H2S.

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