The concentration of HCl in hydrochloric acid is reduced to 12% of its initial value by dilution. What is the difference in the pH values of the two solutions?
In the solutions manual it has
DeltapH = -log(.12[HCl]/[HCl])
How do you know as to cancel out HCl as shown above?
6th edition #12.19 [ENDORSED]
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Re: 6th edition #12.19 [ENDORSED]
If you think about it, let's say the molarity of the initial HCl is 3M. If the final molarity is reduced to 12% of its initial, it will be 3M(.12).
(0.12)(3)=(3)
Therefore, you can cancel out the 3's.
(0.12)(3)=(3)
Therefore, you can cancel out the 3's.
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