5G.5 pt.c

Moderators: Chem_Mod, Chem_Admin

Christopher Anisi 2K
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

5G.5 pt.c

Postby Christopher Anisi 2K » Wed Jan 09, 2019 7:25 pm

Why is it when writing the equilibrium constant for the reaction X2 ---> 2X, the answer key included the mol fraction between X and X2? I understand that the equilibrium constant would be written as but I can't understand why they multiplied the mole fraction of the X2 and the mole fraction of X by the initial pressure?

Julia Go 2L
Posts: 60
Joined: Sun Sep 30, 2018 12:17 am
Been upvoted: 1 time

Re: 5G.5 pt.c

Postby Julia Go 2L » Wed Jan 09, 2019 8:20 pm

For this problem, the diatomic molecule X2 is dissociating. This means they are separating into the individual element X. So, the reactant is X2 and the product is X.

We need to balance the equation because of conservation of matter so there is a coefficient of 2 in front of X. Hence, X2 ---> 2X

Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 4 guests