11.33 6th edition

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11.33 6th edition

Postby CaminaB_1D » Tue Jan 15, 2019 4:09 pm

11.33 A 0.500-L reaction vessel at 700. K contains 1.20 mmol SO2(g), 0.50 mmol O2(g), and 0.10 mmol SO3(g). At 700. K, Kc 1.7 106 for the equilibrium 2 SO2(g) O2(g) ∆ 2 SO3(g). (a) Calculate the reaction quotient Qc. (b) Will more SO3(g)
tend to form?

Why do we divide each elements moles by the volume of the reaction vessel when calculating for the reaction quotient

Elizabeth Gallmeister 1A
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Joined: Fri Sep 28, 2018 12:21 am

Re: 11.33 6th edition

Postby Elizabeth Gallmeister 1A » Tue Jan 15, 2019 4:14 pm

In order to calculate the reaction quotient, we need molarities, or concentrations of the products and reactants. We know that concentration is a measure of number of moles divided by volume, so we do just that: put moles over volume to find molarity of each.

Chloe Likwong 2K
Posts: 70
Joined: Fri Sep 28, 2018 12:23 am

Re: 11.33 6th edition

Postby Chloe Likwong 2K » Tue Jan 15, 2019 11:53 pm

Similar to finding the equilibrium constant, the reaction quotient requires you to use molarity/concentration.

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