12.23 6th Edition

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Alexa_Henrie_1I
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12.23 6th Edition

Postby Alexa_Henrie_1I » Thu Jan 17, 2019 9:27 am

Hello, I am having trouble solving 12.23. Could someone please explain how to go about it? The question asks:


The value of Kw for water at body temp (37 degrees C) is 2.1x10^-14. A) What is the molarity of H3O ions and the pH of neutral water at 37 degrees C? B) What is the molarity of OH in neutral water at 37 degrees C?

Chem_Mod
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Re: 12.23 6th Edition

Postby Chem_Mod » Thu Jan 17, 2019 10:03 am

Remember if it is neutral, the concentration of H3O+ and OH- are the same and their product is equal to the Kw

Alexa_Henrie_1I
Posts: 61
Joined: Fri Sep 29, 2017 7:03 am

Re: 12.23 6th Edition

Postby Alexa_Henrie_1I » Thu Jan 17, 2019 3:11 pm

Okay I understand how the Kw is equal to to x^2 now. Thank you.


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