6th Edition Hw #12.69

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6th Edition Hw #12.69

Postby 005115864 » Sun Jan 20, 2019 1:59 pm

Hi can someone please explain how they got the equation Al(H2O)6 +H2O -> H3O + AL(H2O)5OH from the initial given concentration which is 0.055 M AlCl3? I know I have to make an acid/base reaction but why 6 h2os?

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Re: 6th Edition Hw #12.69

Postby ChathuriGunasekera1D » Mon Jan 21, 2019 3:36 pm

Hi! I think this goes back to the coordination compounds that we learned about in 14A. When Al forms coordinate covalent bond, it bonds with 6 other waters.

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