## Method #3

Mya Majewski 1L
Posts: 89
Joined: Fri Sep 25, 2015 3:00 am

### Method #3

I am enrolled in the 11am lecture, but on Monday I had to go to the 1pm and we didn't finish covering Method #3 on Friday in the 11am, could explain explain this one to me and maybe send a picture of the notes from lecture? Thanks!

Emily Ng_4C
Posts: 65
Joined: Fri Sep 28, 2018 12:17 am

### Re: Method #3

Method #3 is focused on the heat capacity, which is the heat required to raise the temp of an object by 1 degree C. The change in heat or enthalpy can be solved by this equation: qp = enthalpy = nCpdeltaT (The p's are subscripts). Cp represents the molar heat capacity at constant pressure. DeltaT is the change in temperature. N represents the mols. Q represents heat. An important thing to note is that there is a system and the surrounding. If heat is given off from the system (deltah = -), then the surroundings absorb the heat. Thus, qsys + qsurr = 0.

Ricky Ma DIS 4E
Posts: 72
Joined: Fri Sep 28, 2018 12:27 am

### Re: Method #3

I think method 3 just gives you the deltaH of formation for the reactions and the deltaH of formation for the products in which you just do deltaH of the products minus the delta H of the reactants. That will give you the overall enthalpy change. It is probably the most straight forward one out of the three.

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