8.31 Sixth Edition

Moderators: Chem_Mod, Chem_Admin

Alexa Tabakian 1A
Posts: 38
Joined: Fri Sep 28, 2018 12:20 am

8.31 Sixth Edition

Postby Alexa Tabakian 1A » Sat Feb 02, 2019 9:29 pm

Calculate the heat released by 5.025 g of Kr at .400 atm as it cools from 97.6 to 25.0 C at (a) a constant pressure and (b) constant volume.

I tried looking this up in the book and it wants to us to use fractions and stuff like that. Is there another way we learned how to do it in class?

Posts: 117
Joined: Fri Sep 28, 2018 12:15 am

Re: 8.31 Sixth Edition

Postby aisteles1G » Sat Feb 02, 2019 9:58 pm

We haven't covered it in class but the book talks about how specific heat at constant volume and pressure is given by 3/2R, 5/2 R, etc. so you would still use the formula q=mC(deltaT) but for C look in the book for the Cv or Cp formula to plug in. the fractions you just have to know I think, maybe they would be given on a test but its a formula so I don't think there is a different way to solve it. Hope this helps!

Jocelyne Milke 1G
Posts: 73
Joined: Fri Sep 28, 2018 12:25 am

Re: 8.31 Sixth Edition

Postby Jocelyne Milke 1G » Sun Feb 03, 2019 3:08 pm

The Cv and Cp constants are given on the constant and equations sheet too

Return to “Thermodynamic Systems (Open, Closed, Isolated)”

Who is online

Users browsing this forum: No registered users and 0 guests