Combustion of Glucose

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Nathan Mariano 2G
Posts: 68
Joined: Fri Sep 28, 2018 12:29 am

Combustion of Glucose

In the example where Dr. Lavelle demonstrated the combustion of glucose, how can we assume that the pressure is constant?

taline_n
Posts: 64
Joined: Fri Sep 28, 2018 12:17 am

Re: Combustion of Glucose

since the reaction is happening out in the open (open system), we can assume that the only pressure acting upon it is atmospheric pressure, which is constant (1 atm).

Aiden Atoori 1C
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

Re: Combustion of Glucose

The reactions only pressure was atmospheric which was constant. This is because it was an open reaction.