Bomb Calorimeter

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Alexandria Ilagan 2A
Posts: 19
Joined: Fri Sep 28, 2018 12:22 am

Bomb Calorimeter

Postby Alexandria Ilagan 2A » Sun Feb 03, 2019 9:42 pm

I am a bit confused about a bomb calorimeter. Can someone explain what is happening inside the system?

Kathryn 1F
Posts: 66
Joined: Fri Sep 28, 2018 12:19 am

Re: Bomb Calorimeter

Postby Kathryn 1F » Sun Feb 03, 2019 9:48 pm

it's supposed to be an isolated system, so the chamber is insulated and the reaction happens inside, with no change of volume. Heat is measured before and after the reaction to find out how much energy was released

Simmi Diwanji 2B
Posts: 32
Joined: Fri Sep 28, 2018 12:20 am

Re: Bomb Calorimeter

Postby Simmi Diwanji 2B » Mon Feb 04, 2019 10:29 pm

A bomb calorimeter is an example of an isolated system, which means that no matter or energy can be transferred in or out of it. This is ideal for experiments where you would like to measure a temperature difference under constant volume where you don't have to worry about heat being transferred from your fingertips to the system because it is all insulated. In a bomb calorimeter, the heat measured is equal to the internal energy change, determined by the temperature change.

Grace Kim 1J
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am
Been upvoted: 1 time

Re: Bomb Calorimeter

Postby Grace Kim 1J » Mon Feb 04, 2019 11:09 pm

Here is a link to a visual representation of a bomb calorimeter and how it works. Basically, the ignition unit start the combustion, and since there is no change in volume, all of the energy is released as heat. This released heat raises the temperature of the surrounding water and the temperature of the water is measured using the thermometer. ... GqiUob6tcM

Hope this helps!

Melissa Bu 1B
Posts: 36
Joined: Fri Sep 28, 2018 12:19 am

Re: Bomb Calorimeter

Postby Melissa Bu 1B » Tue Feb 05, 2019 10:50 pm

Like above comments have mentioned, there is no change in volume in a bomb calorimeter. With this in mind while calculating change in internal energy (delta U) where delta U=q+w and w=-PdeltaV, w would be equal to 0 since delta V is 0. Therefore, the internal energy change (delta U) of a bomb calorimeter is just q.

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