## Expansion work

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Marsenne Cabral 1A
Posts: 59
Joined: Fri Sep 28, 2018 12:19 am

### Expansion work

Can anyone help me with this question?

How much work does 100 g of water do when it freezes at ) degrees Celsius and pushes back the metal wall of a pipe that exerts an opposing pressure of 1070 atm? The densities of water and ice at 0 degrees Celsius are 1.00g/cm^3 and .92 g/cm^3 respectively.

Emily Huang 1E
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

### Re: Expansion work

You would use the equation w=-PdeltaV. To get the final and intial volume you would multiply the grams of water by the density and convert cm3 to L. 1cm3 is 10^-3 L. Then you would use 1070 as the pressure value and plug in deltaV and convert L*atm to Joules to get the final work done.