Homework Question 6th ED

Moderators: Chem_Mod, Chem_Admin

Posts: 72
Joined: Fri Sep 28, 2018 12:28 am

Homework Question 6th ED

Postby Elle_Mendelson_2K » Sat Feb 09, 2019 8:01 pm

Can some one explain chapter 8 #51

Posts: 62
Joined: Fri Sep 28, 2018 12:17 am

Re: Homework Question 6th ED

Postby Sean_Rodriguez_1J » Sat Feb 09, 2019 8:22 pm

You first have to start by finding the enthalpy of the reaction, which you just calculate normally with the values in the appendix and the given one for TNT. You should get -13168kJ. Per mole of TNT (there are 4 in the original reaction), 1/4 of this amount of energy, or 3292 KJ, will be released per mole. Now we need to do some unit conversions. The overall unit conversion would be
(3452 kJ*mol^-1 TNT/ 222.1347 g*mol^-1 ) * (1.65g*cm^-3)* (1000cm^3/1L) = 2.5 * 10^4 kJ * L^-1 when you round for sig figs.

Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 1 guest