## Question 8.19 (Sixth Edition)

Steve Magana 2I
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

### Question 8.19 (Sixth Edition)

Question: (a) Calculate the heat that must be supplied to a 500.0-g copper kettle containing 400.0 g of water to raise its temperature from 22.0 degrees Celsius to the boiling point of water, 100.0 degrees Celsius. (b) What percentage of the heat is used to raise the temperature of the water?

I'm having trouble with this question, can someone help me please? Thank you!

Tam To 1B
Posts: 72
Joined: Fri Sep 28, 2018 12:25 am

### Re: Question 8.19 (Sixth Edition)

So with this question, you want to find q of both the copper and the water and add it together to find the total amount of heat supplied.
You know that q = mCdeltaT
q(copper) = (500 g)(0.38 J/gC)(100-22 C) = 14.82 kJ
q(water) = (400 g)(4.184 J/gC)(100-22 C) = 130.54 kJ
q(total) = 14.82 + 130.54 = 145 kJ

For part (b), you take the heat of the water and divide it by the total since that much is used to raise the temperature of the water. 130.5/145 = 90%.

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

### Re: Question 8.19 (Sixth Edition)

Where did you get 0.38 J/gC?

Ashley Kim
Posts: 62
Joined: Fri Sep 28, 2018 12:19 am
Been upvoted: 1 time

### Re: Question 8.19 (Sixth Edition)

0.38 J/g C is the specific heat capacity of copper.