When a system can only be prepared in one way

Boltzmann Equation for Entropy:

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Katherine Grillo 1B
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When a system can only be prepared in one way

Postby Katherine Grillo 1B » Tue Feb 12, 2019 11:18 pm

What does it mean that a system can only be prepared in one way? And why does that mean S=0?

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Re: When a system can only be prepared in one way

Postby Chem_Mod » Wed Feb 13, 2019 10:52 am

This is referring to when there is only one state/position available to the molecule(s). If there is only 1 position, then W (degeneracy)= 1number of molecules, and 1 raised to any power is still 1, then the ln(1)=0 so if S= kBln(W) then S=0. This tells us that the molecule or molecules do not possess any residual, or positional, entropy.

Christopher Anisi 2K
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Re: When a system can only be prepared in one way

Postby Christopher Anisi 2K » Sat Feb 16, 2019 9:19 pm

That means that the system can only be oriented in one way meaning that it only has one energy state or degeneracy value of 1. And when utilizing S=KBlnW assuming there is only residual energy involved that would give you an entropy value of 0.


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