At Equilibrium G

[305174946]

For the equation G=-RTlnK
when K<1 then G is positive which means R>P right? (non-spontaneous?)
and when K>1 then G is negative which means R<P right? (spontaneous?)

[Samantha Kwock 1D]

Yes, for K < 1, lnK will be negative, cancelling out the negative in -RTlnK. This means that G is positive. For K > 1, lnK will be positive and G will be negative. When G is negative, the reaction is spontaneous.

[Parth Mungra]

If K=0, then the reaction is neither spontaneous nor nonspontaneous

[Dayna Pham 1I]

If K=0, then the reaction is neither spontaneous nor nonspontaneous

This sounds interesting! I’ve never heard of a case where K=0, can someone elaborate on this?

[Dong Hyun Lee 4E]

An example of where K=0 would be the example he went over in class where when T=333K, BR2 was in both liquid and gas phase. This was called the boiling point. And when T was above 333K, the reaction favored foward and when T<333K a reverse reaction was favored.

[904936893]

If K = 0, is the reaction at equilibrium?

[bonnie_schmitz_1F]

If K = 0, is the reaction at equilibrium?

I think so since the reaction is no longer releasing or requiring energy.