## calculating delta G

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

marcus lin 1E
Posts: 54
Joined: Fri Sep 28, 2018 12:28 am

### calculating delta G

If you're given standard conditions of delta H and delta S, will T= 25+273.15 since the standard conditions assume T is at 25 celsius?

whitney_2C
Posts: 74
Joined: Fri Sep 28, 2018 12:28 am

### Re: calculating delta G

Yes, standard conditions assume 298.15 K or 25 degrees Celsius, which one you use in your calculations just depends on the kind that you are doing.

almaochoa2D
Posts: 67
Joined: Fri Sep 28, 2018 12:23 am

### Re: calculating delta G

What do you mean by "what kind you're doing"? I would think that it is always in kelvins.

Posts: 60
Joined: Fri Sep 28, 2018 12:16 am

### Re: calculating delta G

Yes, it would be 298K because T is in Kelvin in the Gibbs free energy equation.

lindsey_ammann_4E
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

### Re: calculating delta G

If given degrees Celsius, convert to K.