delta S

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katherinemurk 2B
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Joined: Wed Nov 15, 2017 3:02 am

delta S

Postby katherinemurk 2B » Wed Feb 13, 2019 10:51 am

under what conditions does delta S = 0

Vy Lu 2B
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Joined: Fri Sep 28, 2018 12:24 am

Re: delta S

Postby Vy Lu 2B » Wed Feb 13, 2019 10:57 am

Delta S (surroundings) is zero under free expansion; delta S (universe) is zero under reversible conditions and equilibrium; delta S (system) should be zero when there is no transfer of heat from and to the system and when the temperature and volume are constant in the system.

Sarah Fatkin 4I
Posts: 71
Joined: Fri Sep 28, 2018 12:27 am

Re: delta S

Postby Sarah Fatkin 4I » Wed Feb 13, 2019 11:02 am

Delta S of the system equals zero when there is no heat entering the system, because detla S = q(reversible)/T.

JiangJC Dis2K
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Joined: Fri Oct 12, 2018 12:16 am

Re: delta S

Postby JiangJC Dis2K » Wed Feb 13, 2019 11:24 am

For a system at equillibrium, the total delta s equals zero. For n irreversible expansion, given that there is no effect on the surroundings, delta s system equals delta s total.

Ian Marquez 2K
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Re: delta S

Postby Ian Marquez 2K » Wed Feb 13, 2019 3:21 pm

Like the replies above, delta S of the universe, or when negative delta S of the system is equal to delta S of the surroundings, is 0 when the reaction is at equilibrium and is reversible. Also, delta U would be 0.

Ashe Chen 2C
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Joined: Mon Jan 07, 2019 8:23 am

Re: delta S

Postby Ashe Chen 2C » Sat Feb 16, 2019 9:55 pm

when q=0, or in free expansion.

Niveda_B_3I
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Re: delta S

Postby Niveda_B_3I » Tue Feb 19, 2019 12:38 pm

The change in entropy would be zero when the heat transferred into or out of the system is 0.

Jonny Schindler 1A
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Re: delta S

Postby Jonny Schindler 1A » Tue Feb 26, 2019 4:34 pm

When volume is constant, changes in pressure/temperature result in a change in entropy


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