Delta G=0 at equilibrium
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Delta G=0 at equilibrium
I understand that at equilibrium, Gibbs free energy change is zero but I'm confused on the conceptual reasoning behind this. Could someone explain this to me?
Re: Delta G=0 at equilibrium
When Gibbs free energy is equal to 0 that means that the reaction is at equilibrium meaning that no more work can be done.
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Re: Delta G=0 at equilibrium
Gibbs free energy is the energy free to do work. At equilibrium, no net energy is being gained or lost (nothing is really changing). Thus, at equilibrium, Delta G is 0.
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Re: Delta G=0 at equilibrium
Gibbs free energy is the free energy in a system. When it is 0, there can be no gain or loss of energy.
Re: Delta G=0 at equilibrium
The total delta G of a reaction equals the total delta G of products minus that of all the reactants. At equilibrium, there is no difference between the delta G of the reactants and the products, so that total delta G equals 0.
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