## Moles in -nFEcell

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Nico Edgar 4L
Posts: 32
Joined: Fri Sep 28, 2018 12:19 am

### Moles in -nFEcell

How do we know what n is? Is it just the sum of the coefficients of the products?

Gillian Murphy 2C
Posts: 30
Joined: Fri Sep 28, 2018 12:22 am

### Re: Moles in -nFEcell

n represents the number of electrons transferred in a balanced redox reaction

varunhariharan
Posts: 30
Joined: Mon Jan 07, 2019 8:16 am

### Re: Moles in -nFEcell

To find n, you must write out both of the half reactions and balance the equations. Once the number of electrons on both sides of the reaction are consistent, this is how many moles should be used in this equation.

Jake Gordon 1A
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

### Re: Moles in -nFEcell

n is the number of moles (stoichiometric coefficent) for the electrons transferred in the balanced redox reaction

Rehan Chinoy 1K
Posts: 67
Joined: Fri Sep 28, 2018 12:25 am

### Re: Moles in -nFEcell

To be clear n is the number of moles of electrons in the balanced redox reaction, not the number of electrons.

Brian Kwak 1D
Posts: 88
Joined: Fri Sep 28, 2018 12:17 am

### Re: Moles in -nFEcell

As everyone stated before n represents the moles of electrons. To figure it out you could do the reduction and oxidation half-reactions for the reaction to calculate it. Balance the reactions so there are equal number of electrons for both the oxidation and reduction half reactions. I just want to note that even if you change the coefficients of the half reactions the E° For the reactions does not change because it is a INTENSIVE property!

Return to “Work, Gibbs Free Energy, Cell (Redox) Potentials”

### Who is online

Users browsing this forum: No registered users and 0 guests