## Quiz1Prep#10

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

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### Quiz1Prep#10

In the green workbook for Chem14A, in quiz 1 preparation, problem number 10 solution uses the Bohr Equation for H-Atom, but instead of multiplying (Z^2/N^2) by Rydberg's constant, it's multiplied by -2.178x10^-18J. Where did this number come from?

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### Re: Quiz1Prep#10

This number 2.18*10^-18 J is the Rydberg energy. It's simply Planck's constant times the Rydberg frequency, or the quantity "hR" that appears in the equation in the course reader