## ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Emmaraf 1K
Posts: 94
Joined: Sat Oct 20, 2018 12:16 am

### ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

We learned this equation in class but to calculate K when not at 25 degrees C yet it's not on our formula sheet. Will it be on the test and if so how would it show up/would we have to memorize it?

Shubham Rai 2C
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

### Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

This is a derived equation from the formula of delta G (standard) = -RTlnK where you solve for K for two different T value. You have to combine the two different T equations to find the equation ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1). So technically it is on the equation sheet, but you can memorize it to not have to go through these steps.

Jonny Schindler 1A
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

### Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

Can anyone provide an example of using this equation?

Selina Bellin 2B
Posts: 62
Joined: Fri Sep 28, 2018 12:25 am

### Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

memorize it and understand where it comes from, but i believe it's also on the test's formula page